If a building has a perimeter of 100 feet and a foundation width of 16 inches, how many cubic yards are required for the foundation?

If a building has a perimeter of 100 feet and a foundation width of 16 inches, how many cubic yards are required for the foundation?

• A. 3 cubic yards
• B. 5 cubic yards
• C. 7 cubic yards
• D. 10 cubic yards

Answer: (B)

To determine how many cubic yards of concrete are needed for the foundation, we first need to calculate the volume of the foundation. 1. **Convert the Foundation Width to Feet**: The foundation width given is 16 inches. To convert inches to feet, divide by 12, since there are 12 inches in a foot: \[ 16 \text{ inches} \div 12 \text{ inches/foot} = \frac{16}{12} = 1.3333 \text{ feet (or } 4/3 \text{ feet)} \] 2. **Calculate the Volume**: The volume of the foundation can be calculated by multiplying the perimeter by the foundation width. The formula for volume is: \[ \text{Volume} = \text{Perimeter} \times \text{Width} \times \text{Depth} \] For simplicity, if we assume a standard depth for the foundation (which is often around 1 foot for preliminary calculations), the volume becomes: \[ \text{Volume} = 100 \text{ feet} \times 1.3333 \text{ feet} \times

To determine how many cubic yards of concrete are needed for the foundation, we first need to calculate the volume of the foundation.

1. Convert the Foundation Width to Feet:

The foundation width given is 16 inches. To convert inches to feet, divide by 12, since there are 12 inches in a foot:

[

16 \text{ inches} \div 12 \text{ inches/foot} = \frac{16}{12} = 1.3333 \text{ feet (or } 4/3 \text{ feet)}

]

2. Calculate the Volume:

The volume of the foundation can be calculated by multiplying the perimeter by the foundation width. The formula for volume is:

[

\text{Volume} = \text{Perimeter} \times \text{Width} \times \text{Depth}

]

For simplicity, if we assume a standard depth for the foundation (which is often around 1 foot for preliminary calculations), the volume becomes:

[

\text{Volume} = 100 \text{ feet} \times 1.3333 \text{ feet} \times